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14th December 2010 20:34 #1
C++ ?

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14th December 2010 20:35 #2
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14th December 2010 20:54 #3
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14th December 2010 21:12 #4Registered User
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Bombera , -. ,
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14th December 2010 21:38 #5

2 2 ( )Code:if(a[i][j]>0&&a[i][j]/2%2!=0)
18/2=9 9%2=1
20/2=10 10%2=0
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14th December 2010 21:42 #6Registered User
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19, ?
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14th December 2010 21:51 #7
int .
19/2=9 9%2=1
9,5
: 21
Last edited by martos1; 14th December 2010 at 22:05.
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14th December 2010 23:21 #8
Bombera, 4 . 47 4, . , - . , .
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14th December 2010 23:30 #9
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(%) - 0(false) - (true).EVGA X299 FTW K|i9-7960X@4.7|4x8 Patriot Viper Steel 4000|GTX 1660 Ti|970 EVO 1 TB|Seasonic Focus GX-1000|Xigmatek Elysium|
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15th December 2010 00:01 #10
. :
C/C++Code:if (a[i][j] & 3 == 2) printf("%d\n", a[i][j]);
Last edited by icaci; 15th December 2010 at 00:24. Reason:
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15th December 2010 02:55 #11
! "== 2" , .
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15th December 2010 20:20 #12



Code:#include <iostream.h> int main() { int a[2][3],i,j; for(i=0;i<2;i++) for(j=0;j<3;j++) { cout<<"a["<<i<<"]["<<j<<"]="; cin>>a[i][j]; } cout<<"Izvejdane na udvoenite nechetni:"<<endl; for(i=0;i<2;i++) for(j=0;j<3;j++) if(a[i][j]>0&&a[i][j]%2==0&&a[i][j]/2%2!=0) cout<<"a["<<i<<"]["<<j<<"]="<<a[i][j]<<endl; return 0; }
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15th December 2010 20:45 #13Registered User
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15th December 2010 22:28 #14, . , . ...
Originally Posted by Bombera

- , icaci , 4, 2, 2. 2 4. - "".Fujistu Lifebook E756 | Core i7-6500U / 400MHz-3.1GHz | 8 GB DDR4-2133 | Samsung PM871 / 256 GB SSD | 15" 1920x1080 | Manjaro Linux + kernel 4.19
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15th December 2010 22:45 #15
@martos1,
- 1 , . , ,Code:a[i][j] > 0
Code:if (a[i][j] & 3 == 2)
4eRNoBiL. , - .Code:if (a[i][j] % 4 == 2)

2? , 1 , 2 0 , ...10, 2. 2k+1, k , 2 4k+2, , 4 2. , , .Last edited by icaci; 15th December 2010 at 22:55.
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15th December 2010 23:35 #16




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