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  1. #1
    Registered User
    Join Date: Sep:2008
    Location: PC
    Posts: 122

    Question .

    Code:
    #include <stdio.h>
    int main()
    {
        int s[10],i;
    
        for(i=1; i<11; i++) s[i-1]=i*i;
        for(i=0; i<10; i++) printf("%d ", s[i]);
    
        return 0;
    }
    .
    1 10. s[i-1] ?? .

  2. #2
    Registered abUser ike's Avatar
    Join Date: Jul:2004
    Location: sofi
    Posts: 4,965
    s 10 0 9, 1 10, s[0] e 1*1, s[1] e 2*2 ... s[9] 10*10.

    for(i=1; i<11; i++) s[i-1]=i*i;
    :
    for(i=0; i<10; i++) s[i]=(i+1)*(i+1);

    , s[0].
    Have no fear ike iz here.
    CPU Cx486DLC@40MHz, RAM 4MB, VGA Trident 512KB, HDD Conner 160MB, Monitor 14" Color

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