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1st June 2004 20:14 #1
!!!!
, , , , . 6 .
:
sinA + sin2A + sin3A
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4cosA . cosA . sin3A
----2------------2
. .
9999999Ad astra per aspera - To the stars through difficulties
Nvidia - The way you are meant to be played!
Blog - http://poseyd0n.blogspot.com/
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1st June 2004 21:48 #2
! ,
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i3-12100f@5.1Ghz, G. Skill PC4133 B-die, EVGA GTX 1080ti FTW3 Elite
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1st June 2004 22:00 #3
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1st June 2004 22:02 #4Registered User
Join Date: Jun:2003
Location: Sofia
Posts: 53
...
sin3A + sinA = 2*sin2A*cosA
sin2A = 2*sinA*cosA
2*sin2A*cosA + 2*sinA*cosA =
= 2*cosA*(sin2A + sinA) =
= 2*cosA*2*sin(3A/2)*cos(A/2) =
= 4*cos(A/2)*cosA*sin(3A/2)
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1st June 2004 22:12 #5
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1st June 2004 22:16 #6
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1st June 2004 22:16 #7
. . . . .
9999999Ad astra per aspera - To the stars through difficulties
Nvidia - The way you are meant to be played!
Blog - http://poseyd0n.blogspot.com/
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1st June 2004 22:17 #8
....
sqr(sinA(alpha))+sqr(cosB(beta)) = 1It's not about what science can do for you. It's all about what you can do for the science.
ignore list:Zabluden
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1st June 2004 22:24 #9
! . . - 4cosA . cosA . sin3A 4cos(A/2) . cosA . sin(3A/2)




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