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10th June 2005 13:59 #1Registered User
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! 1,2
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z=(x+y^3)/(y+x^2)
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10th June 2005 14:14 #2Z'x= [1*(y+x^2)] - [(x+y^3)*2x] / (y+x^2)^2
Originally Posted by Canis aureus
Z'x= (y+x^2) - 2x*(x+y^3) / (y+x^2)^2
Z'y= 3y*(y+x^2) - (x+y^3)*1 / (y+x^2)^2
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10th June 2005 14:19 #3Registered User
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10th June 2005 15:32 #4
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11th June 2005 03:49 #5
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11th June 2005 10:00 #6
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20th February 2009 00:27 #7
Compliments of Derive 6
, :
http://cs.jsu.edu/~leathrum/Mathlets/derivcalc.htmlLast edited by George; 20th February 2009 at 00:32.
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20th February 2009 03:26 #8
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20th February 2009 03:57 #9
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20th February 2009 10:30 #10
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20th February 2009 10:48 #11




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